M x T= 4Ever
This, of course, led to some interesting things, such as:
M= 4Ever/T
T=4Ever/M
Thus,
M x T = 4Ever, but, T= 4Ever/M
Thus,
M x(4Ever/M)=4Ever
Cancel out the M's, and
4Ever=4Ever
Then I thought "Hmmmm....what if I tried to differentiate this equation. Well.....with the equation as it is, it didn't work too well......I started out with each of the parts being a constant, which of course left the derivative as 0. Then, I decided to assign each part of the equation its own "function" (not exactly what it was, but I can't think of the proper term.). Now, I'm a math geek, and so, of course, I've heard the stupid pick up line about someone being sin^2 X, and the other person being cos^2 x, and together they're one. So, I went back to the original M + T= 4Ever, and assigned each thing a value:
M=sin^2 x
T=cos^2 x
4Ever= 1
Then, we have:
sin^2x + cox^2x =1
Take the derivative, and it becomes.....
2sinx -2cosx = 0
Add 2 cos x to both sides, and....
2sinx = 2cos x
Cancel the 2
sin x = cos x
Awww......so, apparently, if M and I were both these functions, and we took the derivatives, we'd be equal... lol. :) From a math perspective, at first glance, this looks to be a false statement. But wait!! what about 45 degrees (pi/4 for those who prefer radians)? isn't the cosine value the same as the sine value there? and what about the angle in the third quadrant? 215 degrees? (5pi/4). And then of course there's infinitely many coterminal angles.....
Thus, using derivatives, trigonometry, I have proved that M' and T' are equal. lol. Well, that's My Crazy Life!
That is awesome!!!!!!! =D
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